Arrange the compounds I,II,and III in decreas | vedclass

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(C) The heat of combustion of a hydrocarbon is directly proportional to the number of carbon atoms present in the molecule.Compound $I$ is ethylcyclop

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$III > II > I$

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(C) The heat of combustion of a hydrocarbon is directly proportional to the number of carbon atoms present in the molecule.Compound $I$ is ethylcyclopentane $(C_7H_{14})$,which has $7$ carbon atoms.Compound $II$ is ethylcyclohexane $(C_8H_{16})$,which has $8$ carbon atoms.Compound $III$ is ethylcycloheptane $(C_9H_{18})$,which has $9$ carbon atoms.Since the number of carbon atoms follows the order $III > II > I$,the heat of combustion also follows the same order: $III > II > I$.

Arrange the compounds $I$,$II$,and $III$ in decreasing order of their heats of combustion.

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