Arrange the following alkanes in decreasing o | vedclass

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(C) For isomeric alkanes,the heat of combustion is inversely proportional to their stability.As branching increases,the stability of the alkane increa

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$(iii) > (ii) > (i)$

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(C) For isomeric alkanes,the heat of combustion is inversely proportional to their stability.As branching increases,the stability of the alkane increases.Stability order: Neopentane > Isopentane > $n$-pentane.Therefore,the order of heat of combustion is: $n$-pentane > Isopentane > Neopentane,which is $(iii) > (ii) > (i)$.Heat of combustion $\propto \frac{1}{	ext{Stability}}$

Arrange the following alkanes in decreasing order of their heats of combustion:
$(i)$ $CH_3-C(CH_3)_2-CH_3$ (Neopentane)
$(ii)$ $CH_3-CH(CH_3)-CH_2-CH_3$ (Isopentane)
$(iii)$ $CH_3-CH_2-CH_2-CH_2-CH_3$ ($n$-pentane)

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Arrange the following alkanes in decreasing order of their heats of combustion:$(i)$ $CH_3-C(CH_3)_2-CH_3$ (Neopentane)$(ii)$ $CH_3-CH(CH_3)-CH_2-CH_3$ (Isopentane)$(iii)$ $CH_3-CH_2-CH_2-CH_2-CH_3$ ($n$-pentane)