Arrange the following bonds in order of increasing ionic character,giving reasons: $N-H$,$F-H$,$C-H$,and $O-H$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The ionic character of a bond is directly proportional to the electronegativity difference between the two bonded atoms. The greater the difference,the more polar (ionic) the bond is.
Bond Electronegativity difference
$C-H$ $2.5 - 2.1 = 0.4$
$N-H$ $3.0 - 2.1 = 0.9$
$O-H$ $3.5 - 2.1 = 1.4$
$F-H$ $4.0 - 2.1 = 1.9$

Based on the electronegativity values,the increasing order of ionic character is:
$C-H < N-H < O-H < F-H$

Explore More

Similar Questions

Identify the element with the lowest electronegativity.

Bond polarity of a diatomic molecule is because of

The electronegativities of $C, N, Si$ and $P$ are in the order of

Electronegativity is a measure of the capacity of an atom to

If $P$,$Q$,$R$ and $S$ are elements of the $3^{rd}$ period of the $p-$block,among these one element is a metal and the rest are non-metals,and their order of electronegativity is given as: $P < Q < R < S$. The chloride compound of which element is hypovalent?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo