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(C) The boiling point of a compound depends on the strength of intermolecular forces.$n-C_4H_{10}$ $(C)$ is an alkane and possesses only weak van der

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$C < D < B < A$

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(C) The boiling point of a compound depends on the strength of intermolecular forces.$n-C_4H_{10}$ $(C)$ is an alkane and possesses only weak van der Waals forces, resulting in the lowest boiling point.$C_2H_5NHC_2H_5$ $(D)$ is a secondary amine; it exhibits hydrogen bonding, but the extent is less than that of a primary amine due to steric hindrance.$n-C_4H_9NH_2$ $(B)$ is a primary amine, which has stronger hydrogen bonding compared to the secondary amine $(D)$.$n-C_4H_9OH$ $(A)$ is an alcohol, which forms the strongest hydrogen bonds due to the high electronegativity of oxygen compared to nitrogen, resulting in the highest boiling point.Therefore, the increasing order of boiling points is $C < D < B < A$.

Arrange the following compounds according to increasing order of boiling points: $n-C_4H_9OH$ $(A)$, $n-C_4H_9NH_2$ $(B)$, $n-C_4H_{10}$ $(C)$, and $C_2H_5NHC_2H_5$ $(D)$.

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