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(B) The rate of $SN_1$ reaction depends on the stability of the carbocation intermediate formed.In these compounds,the carbocation formed is a substit

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$III > IV > II > I$

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(B) The rate of $SN_1$ reaction depends on the stability of the carbocation intermediate formed.In these compounds,the carbocation formed is a substituted benzyl carbocation $(Ar-CH_2^+)$.The stability of the carbocation is increased by the electron-donating effect ($+I$ and hyperconjugation) of the alkyl group attached at the para position.The order of electron-donating ability of the alkyl groups is: isopropyl $(>(CH_3)_2CH-)$ > ethyl $(>CH_3CH_2-)$ > methyl $(>CH_3-)$.Therefore,the stability of the carbocations follows the order: $III > IV > II > I$.Thus,the decreasing order of the rate of hydrolysis is $III > IV > II > I$.

Arrange the following compounds in order of decreasing rate of hydrolysis for $SN_1$ reaction:
$(I)$ $C_6H_5CH_2Br$
$(II)$ $p-CH_3-C_6H_4-CH_2Br$
$(III)$ $p-(CH_3)_2CH-C_6H_4-CH_2Br$
$(IV)$ $p-CH_3CH_2-C_6H_4-CH_2Br$

Similar Questions

Which of the following substances yields benzoic acid upon oxidation?

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$(i)$ Cyclohexylmethyl chloride and Chlorocyclohexane
(ii) $n$-Butyl iodide and $n$-Butyl chloride

Rank the following groups in order of decreasing leaving group ability:
$(i)$ $-OSO_2C_6H_4CH_3$ (tosylate)
(ii) $-OCOCH_3$ (acetate)
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(iv) $-OSO_2CF_3$ (triflate)

Which of the following can be used as the halide component for Friedel-Crafts reaction?

The structure of product $(A)$ is:

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Arrange the following compounds in order of decreasing rate of hydrolysis for $SN_1$ reaction:$(I)$ $C_6H_5CH_2Br$$(II)$ $p-CH_3-C_6H_4-CH_2Br$$(III)$ $p-(CH_3)_2CH-C_6H_4-CH_2Br$$(IV)$ $p-CH_3CH_2-C_6H_4-CH_2Br$