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(A) The boiling point $(BP)$ depends on the intermolecular forces of attraction.$1$. $CH_3CH_2OH$ $(II)$ exhibits strong intermolecular $H$-bonding,re

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$II > I > III > IV$

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(A) The boiling point $(BP)$ depends on the intermolecular forces of attraction.$1$. $CH_3CH_2OH$ $(II)$ exhibits strong intermolecular $H$-bonding,resulting in the highest $BP$.$2$. $CH_3CHO$ $(I)$ is a polar molecule with dipole-dipole interactions,giving it a higher $BP$ than ethers and alkanes.$3$. $CH_3OCH_3$ $(III)$ is a polar ether with weaker dipole-dipole interactions compared to aldehydes.$4$. $CH_3CH_2CH_3$ $(IV)$ is a non-polar alkane with only weak London dispersion forces,resulting in the lowest $BP$.Therefore,the decreasing order of $BP$ is $II > I > III > IV$.

Arrange the following compounds in decreasing order of their boiling point $(BP)$:
$CH_3CHO$ $(I)$,$CH_3CH_2OH$ $(II)$
$CH_3OCH_3$ $(III)$,$CH_3CH_2CH_3$ $(IV)$

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Arrange the following compounds in decreasing order of their boiling point $(BP)$:$CH_3CHO$ $(I)$,$CH_3CH_2OH$ $(II)$$CH_3OCH_3$ $(III)$,$CH_3CH_2CH_3$ $(IV)$