Arrange the following labelled hydrogens in d | vedclass

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(A) The acidity of the protons depends on the stability of the conjugate base formed after the removal of the proton.$1$. Proton $b$ is part of a carb

Vedclass · Accepted Answer

$b > c > d > a$

Vedclass · Answer

(A) The acidity of the protons depends on the stability of the conjugate base formed after the removal of the proton.$1$. Proton $b$ is part of a carboxylic acid group $(-COOH)$. The conjugate base (carboxylate ion,$-COO^	heta$) is stabilized by equivalent resonance.$2$. Protons $c$ and $d$ are phenolic protons ($-OH$ attached to an aromatic ring). The conjugate base is a phenoxide ion,which is stabilized by resonance,but less so than the carboxylate ion.$3$. Proton $a$ is an acetylenic proton $(-C \equiv CH)$. The conjugate base is an acetylide ion $(-C \equiv C^	heta)$,which is the least stable among these due to the lack of resonance stabilization.$4$. Comparing $c$ and $d$: Proton $c$ is ortho to an electron-withdrawing $-NO_2$ group (via the aromatic ring system),which increases its acidity compared to $d$ through the inductive effect.Thus,the order of acidity is $b > c > d > a$.

Column-$I$ (formula)	Column-$II$ (name)
$A$. $RCH=NH$	$i$. Diisobutyl aluminium hydride
$B$. $AlH(i-Bu)_2$	$ii$. Benzalchloride
$C$. $C_6H_5-CH(OCOCH_3)_2$	$iii$. Imine
$D$. $C_6H_5CHCl_2$	$iv$. Benzylidene diacetate

Arrange the following labelled hydrogens in decreasing order of acidity.

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Show how each of the following compounds can be converted to benzoic acid.
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Match the formulas in Column-$I$ with their names in Column-$II$.

Column-$I$ (formula) Column-$II$ (name)

$A$. $RCH=NH$ $i$. Diisobutyl aluminium hydride

$B$. $AlH(i-Bu)_2$ $ii$. Benzalchloride

$C$. $C_6H_5-CH(OCOCH_3)_2$ $iii$. Imine

$D$. $C_6H_5CHCl_2$ $iv$. Benzylidene diacetate

$CH_3-CO-CH_2-COOC_2H_5 \xrightarrow{NaOH, H_2O} A$. The product '$A$' in the reaction is

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$2-\text{hydroxycyclohexylacetone}$ $\xrightarrow{I_2/NaOH}$ $\xrightarrow{\Delta}$ $\xrightarrow{H^+}$ $\xrightarrow{\Delta} A$
$A$ is:

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