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(A) The displacement of metals from their salt solutions is determined by their position in the electrochemical series. $A$ metal with a more negative

Vedclass · Accepted Answer

$Mg > Al > Zn > Fe > Cu$

Vedclass · Answer

(A) The displacement of metals from their salt solutions is determined by their position in the electrochemical series. $A$ metal with a more negative standard reduction potential can displace a metal with a more positive standard reduction potential from its salt solution.The standard reduction potentials $(E^\circ)$ are:$Mg^{2+} + 2e^- \rightarrow Mg$ $(-2.37 \ V)$$Al^{3+} + 3e^- \rightarrow Al$ $(-1.66 \ V)$$Zn^{2+} + 2e^- \rightarrow Zn$ $(-0.76 \ V)$$Fe^{2+} + 2e^- \rightarrow Fe$ $(-0.44 \ V)$$Cu^{2+} + 2e^- \rightarrow Cu$ $(+0.34 \ V)$Since the reactivity (displacing power) increases as the reduction potential becomes more negative,the order of displacement is $Mg > Al > Zn > Fe > Cu$.

Arrange the following metals in the order in which they displace each other from the solution of their salts: $Al$,$Cu$,$Fe$,$Mg$,and $Zn$.

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