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(A) The strength of intermolecular forces in polymers follows the order: Fibres > Thermoplastics > Elastomers.$1$. $Nylon-6$ $(A)$ is a fibre,which co

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$A > C > B$

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(A) The strength of intermolecular forces in polymers follows the order: Fibres > Thermoplastics > Elastomers.$1$. $Nylon-6$ $(A)$ is a fibre,which contains strong hydrogen bonding between the polymer chains,resulting in the strongest intermolecular forces.$2$. $Polyvinyl$ $chloride$ $(C)$ is a thermoplastic,which has dipole-dipole interactions that are stronger than the weak van der Waals forces found in elastomers but weaker than hydrogen bonds.$3$. $Neoprene$ $(B)$ is an elastomer,which has weak van der Waals forces between the polymer chains,making it the weakest among the three.Therefore,the correct order of strength is $A > C > B$.

Arrange the following polymers in order of increasing strength of their intermolecular forces:
$Nylon-6$ $(A)$,$Neoprene$ $(B)$,$Polyvinyl$ $chloride$ $(C)$

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Arrange the following polymers in order of increasing strength of their intermolecular forces:$Nylon-6$ $(A)$,$Neoprene$ $(B)$,$Polyvinyl$ $chloride$ $(C)$