Arrange the following free radicals in order | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of free radicals depends on the degree of substitution and resonance stabilization.$(A)$ is a primary $(1^{\circ})$ alkyl radical: $

Vedclass · Accepted Answer

$C > B > A$

Vedclass · Answer

(C) The stability of free radicals depends on the degree of substitution and resonance stabilization.$(A)$ is a primary $(1^{\circ})$ alkyl radical: $R-CH_2•$.$(B)$ is a secondary $(2^{\circ})$ alkyl radical: $R-CH(CH_3)•$. Secondary radicals are more stable than primary radicals due to increased hyperconjugation and inductive effects.$(C)$ is an allylic radical: $Cyclohexylidene-CH-CH_2•$. This radical is resonance-stabilized by the adjacent double bond,making it the most stable among the three.Therefore,the order of decreasing stability is $C > B > A$.

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation

Arrange the following free radicals in order of decreasing stability:
$(A)$ Cyclohexyl-CH2-CH2•
$(B)$ Cyclohexyl-$CH$•-CH3
$(C)$ Cyclohexyl=$CH$-CH2•
(Note: The dot represents the radical center.)

Similar Questions

What is the order of stability of carbon free radicals among ${3^\circ}$,${2^\circ}$,${1^\circ}$,and $\mathop C\limits^\bullet {H_3}$?

Intermediates formed in the reactions $P$ and $Q$ are:
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$

For the given reaction,the total number of possible products formed by the tertiary carbocation of $A$ is $.........$.

The intermediates in heteropolar reactions are

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following free radicals in order of decreasing stability:$(A)$ Cyclohexyl-CH2-CH2•$(B)$ Cyclohexyl-$CH$•-CH3$(C)$ Cyclohexyl=$CH$-CH2•(Note: The dot represents the radical center.)