Arrange the given steps of expiration in the | vedclass

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(A) The process of expiration occurs in the following sequence:$1.$ Relaxation of the diaphragm and the intercostal muscles returns the diaphragm and

Vedclass · Accepted Answer

$I \rightarrow II \rightarrow IV \rightarrow III$

Vedclass · Answer

(A) The process of expiration occurs in the following sequence:$1.$ Relaxation of the diaphragm and the intercostal muscles returns the diaphragm and sternum to their normal positions $(I)$.$2.$ This movement reduces the thoracic volume and,consequently,the pulmonary volume $(II)$.$3.$ The reduction in pulmonary volume leads to an increase in intra-pulmonary pressure to a level slightly above the atmospheric pressure $(IV)$.$4.$ This pressure gradient causes the air to be expelled from the lungs,which is known as expiration $(III)$.Therefore,the correct sequence is $I \rightarrow II \rightarrow IV \rightarrow III$.

Arrange the given steps of expiration in the sequence of events occurring first:
$I.$ Relaxation of the diaphragm and sternum
$II.$ Reduction of the pulmonary volume
$III.$ Expulsion of air from the lungs
$IV.$ Increase in intra-pulmonary pressure
Choose the correct option.

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$(d)$ Increase in intra-pulmonary pressure

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Arrange the given steps of expiration in the sequence of events occurring first:$I.$ Relaxation of the diaphragm and sternum$II.$ Reduction of the pulmonary volume$III.$ Expulsion of air from the lungs$IV.$ Increase in intra-pulmonary pressureChoose the correct option.