Arrange the hydrides NH_3,HF,H_2O,and HCl in | vedclass

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Question

(A) $H_2O$,$HF$,and $NH_3$ exhibit hydrogen bonding as the intermolecular force,whereas $HCl$ possesses weaker dipole-dipole interactions.Thus,$HCl$ h

Vedclass · Accepted Answer

$HCl < NH_3 < HF < H_2O$

Vedclass · Answer

(A) $H_2O$,$HF$,and $NH_3$ exhibit hydrogen bonding as the intermolecular force,whereas $HCl$ possesses weaker dipole-dipole interactions.Thus,$HCl$ has the lowest boiling point.Among $H_2O$,$HF$,and $NH_3$,$H_2O$ has the highest boiling point due to an extensive network of hydrogen bonds.Between $NH_3$ and $HF$,$HF$ forms stronger hydrogen bonds due to the very high electronegativity of fluorine.Therefore,the increasing order of boiling points is: $HCl < NH_3 < HF < H_2O$.

Arrange the hydrides $NH_3$,$HF$,$H_2O$,and $HCl$ in the increasing order of their boiling points.

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