Arrange the oxides CrO,CrO_3,and Cr_2O_3 in t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acidic strength of metal oxides increases with an increase in the oxidation state of the metal. Calculating the oxidation states of $Cr$ in th

Vedclass · Accepted Answer

$CrO_3 > Cr_2O_3 > CrO$

Vedclass · Answer

(A) The acidic strength of metal oxides increases with an increase in the oxidation state of the metal. Calculating the oxidation states of $Cr$ in the given oxides: $1$. In $CrO$,the oxidation state of $Cr$ is $+2$. $2$. In $Cr_2O_3$,the oxidation state of $Cr$ is $+3$. $3$. In $CrO_3$,the oxidation state of $Cr$ is $+6$. Since the acidic character is directly proportional to the oxidation state,the order of acidic strength is: $CrO_3 (+6) > Cr_2O_3 (+3) > CrO (+2)$.

Column-$I$	Column-$II$
$A$. $Pb_3O_4$	$I$. Neutral oxide
$B$. $N_2O$	$II$. Acidic oxide
$C$. $Mn_2O_7$	$III$. Basic oxide
$D$. $Bi_2O_3$	$IV$. Mixed oxide

Arrange the oxides $CrO$,$CrO_3$,and $Cr_2O_3$ in the decreasing order of acidic strength.

Similar Questions

How would you account for the increasing oxidising power in the series $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$?

Match the formulas given in Column-$I$ with the type of oxide given in Column-$II$ and select the correct option:-

Column-$I$ Column-$II$

$A$. $Pb_3O_4$ $I$. Neutral oxide

$B$. $N_2O$ $II$. Acidic oxide

$C$. $Mn_2O_7$ $III$. Basic oxide

$D$. $Bi_2O_3$ $IV$. Mixed oxide

The incorrect statement$(s)$ among $(a)-(c)$ is (are) :-
$(a)$ $W(VI)$ is more stable than $Cr(VI)$
$(b)$ In the presence of $HCl$,permanganate titrations provide satisfactory results.
$(c)$ Some lanthanoid oxides can be used as phosphors.

The highest Mn fluoride is $MnF_4$ whereas the highest oxide is $Mn_2O_7$, because . . . . . . .

Explain the trends in $E_{M^{3+}/M^{2+}}^{o}$ electrode potential.

Vedclass Test Series

Exam Paper Generator

Online Exam Module