As a result of a change in the magnetic flux linked to the closed loop as shown in the figure,an $e.m.f.$ $V$ volt is induced in the loop. The work done (in joule) in taking a charge $Q$ coulomb once along the loop is

The area of a coil is $A$. The coil is placed in a magnetic field which changes from $B_{0}$ to $4 B_{0}$ in time $t$. The magnitude of the induced e.m.f. in the coil will be:

$A$ square loop of side $10 \ cm$ and resistance $0.7 \ \Omega$ is placed vertically in the east-west plane. $A$ uniform magnetic field of $0.20 \ T$ is set up across the plane in the north-east direction. The magnetic field is decreased to zero in $1 \ s$ at a steady rate. Then,the magnitude of the induced emf is $\sqrt{x} \times 10^{-3} \ V$. The value of $x$ is . . . . . . .

There are two coils $A$ and $B$ as shown in the figure. No current flows in $B$ if $A$ is at rest. Now,the coil $A$ is made to rotate about a vertical axis. At the shown instant $(t=0)$,what will be the direction of the current in coil $A$,when the induced current in coil $B$ is counterclockwise?

$A$ system $S$ consists of two coils $A$ and $B$. The coil $A$ carries a steady current $I$. The coil $B$ is suspended nearby as shown in the figure. If the system is heated,so as to raise the temperature of the two coils steadily,then:

In the figure,a conducting ring of certain resistance is falling towards a current-carrying straight long conductor. The ring and conductor are in the same plane. Then,the: