As shown in the figure, a liquid is at the same level in both arms of a $U$-tube of uniform cross-section when at rest. If the $U$-tube moves with an acceleration '$f$' towards the right, the difference between the liquid heights in the two arms of the $U$-tube will be (acceleration due to gravity $= g$):

  • A
    $\frac{f}{g} a$
  • B
    $\frac{g}{f} a$
  • C
    $a$
  • D
    $\frac{f a}{g}$

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