As the p-character increases,the bond angle i | vedclass

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(A) As the $p-$character increases,the bond angle decreases.For $sp$ hybridization,the $p-$character is $\frac{1}{2}$ $(50\%)$,and the bond angle is $

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Decreases

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(A) As the $p-$character increases,the bond angle decreases.For $sp$ hybridization,the $p-$character is $\frac{1}{2}$ $(50\%)$,and the bond angle is $180^{\circ}$.For $sp^2$ hybridization,the $p-$character is $\frac{2}{3}$ $(\approx 66.7\%)$,and the bond angle is $120^{\circ}$.For $sp^3$ hybridization,the $p-$character is $\frac{3}{4}$ $(75\%)$,and the bond angle is $109.5^{\circ}$.Thus,as the $p-$character increases,the bond angle decreases.

As the $p-$character increases,the bond angle in hybrid orbitals formed by $s$ and $p$ atomic orbitals

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