(D) In group $14$ (or $IVA$),the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. $Pb$ is at the bottom of

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(D) In group $14$ (or $IVA$),the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. $Pb$ is at the bottom of the group,so $Pb^{2+}$ is much more stable than $Pb^{4+}$. $I^-$ is a mild reducing agent and cannot oxidize $Pb^{2+}$ to $Pb^{4+}$. Therefore,$PbI_4$ is not a stable compound. Both the Assertion and the Reason are incorrect.

Class 11 Chemistry p-Block Elements (Class 11)Carbon family

Medium

Assertion : $PbI_4$ is a stable compound.
Reason : Iodide stabilizes higher oxidation state.

AIIMS 2003 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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In the following reaction,assign the product of complete hydrolysis at $R.T.$ for the underlined atom:
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$SiCl_4$ on hydrolysis forms '$X$' and $HCl$. Compound '$X$' loses water at $1000^{\circ} C$ and gives '$Y$'. Compounds '$X$' and '$Y$' respectively are:

MediumAP EAMCET 2009

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Assertion : $PbI_4$ is a stable compound.Reason : Iodide stabilizes higher oxidation state.

Similar Questions

In the following reaction,assign the product of complete hydrolysis at $R.T.$ for the underlined atom:$\underline{Si}O_2 + H_2O \longrightarrow $ No reaction

Which of the following is used for making optical instruments?

$SiCl_4$ on hydrolysis forms '$X$' and $HCl$. Compound '$X$' loses water at $1000^{\circ} C$ and gives '$Y$'. Compounds '$X$' and '$Y$' respectively are:

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Assertion : $PbI_4$ is a stable compound.
Reason : Iodide stabilizes higher oxidation state.

In the following reaction,assign the product of complete hydrolysis at $R.T.$ for the underlined atom:
$\underline{Si}O_2 + H_2O \longrightarrow $ No reaction