Assertion : $1, 3-$ Butadiene is the monomer for natural rubber.
Reason : Natural rubber is formed through anionic addition polymerization.
Reason : Natural rubber is formed through anionic addition polymerization.
- AIf both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- BIf both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- CIf the Assertion is correct but Reason is incorrect.
- DIf both the Assertion and Reason are incorrect.
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. $2$-Chloro-$1,3$-butadiene $I$. Biodegradable polymer $B$. Nylon-$2$-nylon-$6$ $II$. Synthetic Rubber $C$. Polyacrylonitrile $III$. Polyester $D$. Dacron $IV$. Addition Polymer
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $A$. $2$-Chloro-$1,3$-butadiene | $I$. Biodegradable polymer |
| $B$. Nylon-$2$-nylon-$6$ | $II$. Synthetic Rubber |
| $C$. Polyacrylonitrile | $III$. Polyester |
| $D$. Dacron | $IV$. Addition Polymer |
Choose the correct answer from the options given below:
Which of the following statements is incorrect?
Easy
View SolutionWhich of the following is the correct formula for the given polymer?
Medium
View SolutionMatch the polymers given in Column-$I$ with their commercial names given in Column-$II$.
Column-$I$ Column-$II$ $A$. Polyester of glycol and phthalic acid $i$. Novolac $B$. Copolymer of $1,3$-butadiene and styrene $ii$. Glyptal $C$. Phenol and formaldehyde resin $iii$. Buna-$S$ $D$. Polyester of glycol and terephthalic acid $iv$. Buna-$N$ $E$. Copolymer of $1,3$-butadiene and acrylonitrile $v$. Dacron
| Column-$I$ | Column-$II$ |
| $A$. Polyester of glycol and phthalic acid | $i$. Novolac |
| $B$. Copolymer of $1,3$-butadiene and styrene | $ii$. Glyptal |
| $C$. Phenol and formaldehyde resin | $iii$. Buna-$S$ |
| $D$. Polyester of glycol and terephthalic acid | $iv$. Buna-$N$ |
| $E$. Copolymer of $1,3$-butadiene and acrylonitrile | $v$. Dacron |
Medium
View SolutionMatch the following:
List-$I$ List-$II$ $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ $I$. Cross-linked network $B$. Nylon-$6,6$ $II$. Elastomer $C$. $HDP$ $III$. Fibre $D$. Melamine-formaldehyde $IV$. Ziegler-Natta catalyst
| List-$I$ | List-$II$ |
|---|---|
| $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ | $I$. Cross-linked network |
| $B$. Nylon-$6,6$ | $II$. Elastomer |
| $C$. $HDP$ | $III$. Fibre |
| $D$. Melamine-formaldehyde | $IV$. Ziegler-Natta catalyst |
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