Assertion : Iodide ion combines with smaller | vedclass

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(C) The reaction of anisole $(C_6H_5OCH_3)$ with $HI$ involves the protonation of the oxygen atom,followed by the nucleophilic attack of the iodide io

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If the Assertion is correct but Reason is incorrect.

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(C) The reaction of anisole $(C_6H_5OCH_3)$ with $HI$ involves the protonation of the oxygen atom,followed by the nucleophilic attack of the iodide ion $(I^-)$. The $I^-$ ion attacks the less sterically hindered methyl group $(CH_3)$ to form methyl iodide $(CH_3I)$ and phenol $(C_6H_5OH)$. Therefore,the Assertion is correct as the iodide ion attacks the smaller group. However,the Reason states that it gives iodobenzene and methyl alcohol,which is incorrect; it actually gives phenol and methyl iodide. Thus,the Assertion is correct but the Reason is incorrect.

Column-$I$ (Reactants)	Column-$II$ (Products)
$(A) \ CH_3CH_2CH_2-O-CH_3 + HI \rightarrow$	$(i) \ (CH_3)_3C-I + CH_3CH_2OH$
$(B) \ C_6H_5OCH_2CH_3 + HBr \rightarrow$	$(ii) \ CH_3CH_2CH_2OH + CH_3I$
$(C) \ (CH_3)_3C-OCH_2CH_3 + HI \rightarrow$	$(iii) \ CH_3CH_2I + C_6H_5OH$
$(D) \ C_6H_5OCH_2CH_3 + \text{conc. } H_2SO_4 + \text{conc. } HNO_3 \rightarrow$	$(iv) \ p-NO_2-C_6H_4-OCH_2CH_3$

Assertion : Iodide ion combines with smaller group to avoid steric hindrance.
Reason : With $HI$,anisole gives iodobenzene and methyl alcohol.

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Assertion : Iodide ion combines with smaller group to avoid steric hindrance. Reason : With $HI$,anisole gives iodobenzene and methyl alcohol.