Assertion :- The maximum charge that can be g | vedclass

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(D) The electric field at the surface of a conductor is given by $E = \frac{\sigma}{\epsilon_0}$,where $\sigma$ is the surface charge density. For a c

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Both Assertion and Reason are true and Reason is the correct explanation of Assertion.

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(D) The electric field at the surface of a conductor is given by $E = \frac{\sigma}{\epsilon_0}$,where $\sigma$ is the surface charge density. For a conductor of a fixed volume,the surface charge density $\sigma$ is higher at regions with smaller radii of curvature (sharp points).When the electric field at the surface exceeds the dielectric strength of the surrounding air (approximately $3 	imes 10^6 \ V/m$),the air undergoes dielectric breakdown,causing charge leakage (corona discharge).Since sharp points reach this critical electric field value at lower total charges compared to smooth surfaces,the maximum charge a conductor can hold depends on its shape. Thus,the Reason correctly explains why the shape affects the maximum charge.

Assertion $:-$ The maximum charge that can be given to a conductor of fixed volume depends on its shape.
Reason $:-$ If the electric field near the conductor is sufficient for dielectric breakdown of air,no more charge can be transferred to it.

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Assertion $:-$ The maximum charge that can be given to a conductor of fixed volume depends on its shape.Reason $:-$ If the electric field near the conductor is sufficient for dielectric breakdown of air,no more charge can be transferred to it.