Assertion (A): The range of a projectile is m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The assertion $(A)$ is true. The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$. For a given initi

Vedclass · Accepted Answer

$(A)$ is true but $(R)$ is false.

Vedclass · Answer

(C) The assertion $(A)$ is true. The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$. For a given initial velocity $u$,the range is maximum when $\sin(2	heta)$ is maximum,i.e.,$\sin(2	heta) = 1$,which implies $2	heta = 90^{\circ}$ or $	heta = 45^{\circ}$.The reason $(R)$ is false. The range $R$ of a projectile depends not only on the angle of projection $	heta$ but also on the initial velocity $u$ and the acceleration due to gravity $g$ $(R = \frac{u^2 \sin(2	heta)}{g})$. Therefore,it does not depend 'only' on the angle of projection.Thus,$(A)$ is true but $(R)$ is false.

Assertion $(A)$: The range of a projectile is maximum when the angle of projection is $45^{\circ}$.
Reason $(R)$: The range of a projectile depends only on the angle of projection.

Similar Questions

$A$ boy weighing $50 \ kg$ finished a long jump at a distance of $8 \ m$. Considering that he moved along a parabolic path and his angle of jump is $45^{\circ}$,his initial $K.E.$ is (in $J$)

$A$ projectile fired with initial velocity $u$ at an angle $\theta$ has a range $R$. If the initial velocity is doubled at the same angle of projection,then the new range will be:

The horizontal range $(R)$ of a projectile is $n$ times its maximum height $(H)$. Find the angle of projection $(\theta_0)$.

The horizontal range of a projectile is $4\sqrt{3}$ times its maximum height. Its angle of projection will be ......... $^\circ$.

If the height of a projectile at a time of $2 \ s$ from the beginning of motion is $60 \ m$,then the time of flight of the projectile is (Acceleration due to gravity $= 10 \ m \ s^{-2}$) (in $s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion $(A)$: The range of a projectile is maximum when the angle of projection is $45^{\circ}$.Reason $(R)$: The range of a projectile depends only on the angle of projection.