Assertion $(A)$: $[B(OH_2)_6]^{3+}$ and $[B(OH)_4]^{-}$ form octahedral and tetrahedral structures.
Reason $(R)$: Being electron deficient, boron readily reacts with Lewis bases like $H_2O$ and $OH^{-}$.
The correct option among the following is

  • A
    $A$ is true, $R$ is true and $R$ is the correct explanation for $A$
  • B
    $A$ is true, $R$ is true but $R$ is not the correct explanation for $A$
  • C
    $A$ is true but $R$ is false
  • D
    $A$ is false but $R$ is true

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Similar Questions

Identify the correct statements about $p$-block elements and their compounds.
$(A)$ Non-metals have higher electronegativity than metals.
$(B)$ Non-metals have lower ionisation enthalpy than metals.
$(C)$ Compounds formed between highly reactive non-metals and highly reactive metals are generally ionic.
$(D)$ The non-metal oxides are generally basic in nature.
$(E)$ The metal oxides are generally acidic or neutral in nature.

Explain the following:
$(1)$ Gallium has higher ionisation enthalpy than aluminum.
$(2)$ Boron does not exist as $B^{3+}$ ion.

Difficult
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Which base among the following reacts with diborane to cleave it unsymmetrically?

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