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(C) The given reaction is $Pb_3O_4 + 8HCl \xrightarrow{	ext{Warm}} 3PbCl_2 + Cl_2 + 4H_2O$.In $Pb_3O_4$,the oxidation state of $Pb$ is $+\frac{8}{3}$

Vedclass · Accepted Answer

$C$. for either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) The given reaction is $Pb_3O_4 + 8HCl \xrightarrow{	ext{Warm}} 3PbCl_2 + Cl_2 + 4H_2O$.In $Pb_3O_4$,the oxidation state of $Pb$ is $+\frac{8}{3}$.In $PbCl_2$,the oxidation state of $Pb$ is $+2$.In $Cl_2$,the oxidation state of $Cl$ is $0$,while in $HCl$ and $PbCl_2$,it is $-1$.This is an intermolecular redox reaction where $Pb$ is reduced from $+\frac{8}{3}$ to $+2$ and $Cl^-$ is oxidized to $Cl_2$.Therefore,the correct classification is $C$.

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Pb_3O_4 + 8HCl \xrightarrow{\text{Warm}} 3PbCl_2 + Cl_2 + 4H_2O$

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Assign $A$,$B$,$C$,$D$ from the given type of reaction.$Pb_3O_4 + 8HCl \xrightarrow{\text{Warm}} 3PbCl_2 + Cl_2 + 4H_2O$