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(C) In the given reaction: $H_3PO_2 + CuSO_4 + H_2O \longrightarrow Cu + H_3PO_4 + H_2SO_4$The oxidation state of $Cu$ changes from $+2$ in $CuSO_4$ t

Vedclass · Accepted Answer

$C$. For either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) In the given reaction: $H_3PO_2 + CuSO_4 + H_2O \longrightarrow Cu + H_3PO_4 + H_2SO_4$The oxidation state of $Cu$ changes from $+2$ in $CuSO_4$ to $0$ in $Cu$ (reduction).The oxidation state of $P$ changes from $+1$ in $H_3PO_2$ to $+5$ in $H_3PO_4$ (oxidation).Since two different elements (or species) are undergoing oxidation and reduction in an intermolecular manner,this is an intermolecular redox reaction.Also,$Cu$ is displaced from $CuSO_4$ by the reducing agent $H_3PO_2$,making it a displacement reaction.Therefore,the correct classification is $C$.

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$H_3PO_2 + CuSO_4 + H_2O \longrightarrow Cu + H_3PO_4 + H_2SO_4$

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Assign $A$,$B$,$C$,$D$ from the given type of reaction.$H_3PO_2 + CuSO_4 + H_2O \longrightarrow Cu + H_3PO_4 + H_2SO_4$