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(C) In the given reaction: $3PbS + 8HNO_3 \longrightarrow 3Pb(NO_3)_2 + 3S + 2NO + 4H_2O$$1$. Oxidation state of $S$ in $PbS$ is $-2$ and it changes t

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for either intermolecular redox reaction or displacement reaction.

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(C) In the given reaction: $3PbS + 8HNO_3 \longrightarrow 3Pb(NO_3)_2 + 3S + 2NO + 4H_2O$$1$. Oxidation state of $S$ in $PbS$ is $-2$ and it changes to $0$ in $S$. Thus,$S$ is oxidized.$2$. Oxidation state of $N$ in $HNO_3$ is $+5$ and it changes to $+2$ in $NO$. Thus,$N$ is reduced.$3$. Since the oxidation and reduction occur in different species ($PbS$ and $HNO_3$),this is an intermolecular redox reaction.$4$. Additionally,$Pb$ displaces $H$ or acts as a displacement-type redox process where $S^{2-}$ is oxidized to $S^0$ and $N^{5+}$ is reduced to $N^{2+}$.Therefore,the reaction is an intermolecular redox reaction.

Assign $A, B, C, D$ from the given type of reaction.
$3PbS + 8HNO_3 \text{ (dil.)} \longrightarrow 3Pb(NO_3)_2 + 3S \downarrow + 2NO + 4H_2O$

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Assign $A, B, C, D$ from the given type of reaction.$3PbS + 8HNO_3 \text{ (dil.)} \longrightarrow 3Pb(NO_3)_2 + 3S \downarrow + 2NO + 4H_2O$