Assume each reaction is carried out in an ope | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by the equation: $\Delta H = \Delta E + \De

Vedclass · Accepted Answer

$H_{2_{(g)}} + Br_{2_{(g)}} \rightarrow 2HBr_{(g)}$

Vedclass · Answer

(B) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by the equation: $\Delta H = \Delta E + \Delta n_{g} RT$.For $\Delta H = \Delta E$ to hold true,the change in the number of moles of gaseous species $(\Delta n_{g})$ must be $0$.Calculating $\Delta n_{g}$ for option $B$: $H_{2_{(g)}} + Br_{2_{(g)}} ightarrow 2HBr_{(g)}$.$\Delta n_{g} = (	ext{moles of gaseous products}) - (	ext{moles of gaseous reactants}) = 2 - (1 + 1) = 0$.Since $\Delta n_{g} = 0$,it follows that $\Delta H = \Delta E$.

Assume each reaction is carried out in an open container. For which reaction will $\Delta H = \Delta E$ ?

Similar Questions

Identify the pair in which both are not extensive properties.

Calculate the work done during compression of $2 \ mol$ of an ideal gas from a volume of $1 \ m^3$ to $10 \ dm^3$ at $300 \ K$ against a constant external pressure of $100 \ kPa.$

Extensive properties depend on the quantity of matter,while intensive properties do not. Classify the following properties as extensive or intensive:
Mass,internal energy,pressure,heat capacity,molar heat capacity,density,mole fraction,specific heat,temperature,and molarity.

What is the internal energy change when $2$ moles of an ideal gas at $25^{\circ} C$ is compressed isothermally and reversibly from $1.0 \ bar$ to $10.0 \ bar$?

For a reversible process at $T = 300 \, K$,the volume increases from $V_i = 1 \, L$ to $V_f = 10 \, L$. If the process is isothermal,find the value of $\Delta H$ in $kJ$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module