Assuming ideal behaviour,the enthalpy and volume of mixing of two liquids respectively,are

At $373 \ K$,heptane and octane form an ideal solution. The vapor pressures of the two pure liquid components (heptane and octane) are $105 \ kPa$ and $45 \ kPa$,respectively. The vapor pressure of the solution formed by mixing $25 \ g$ of heptane and $35 \ g$ of octane is ........ $kPa$. (Molar masses of heptane and octane are $100 \ g \ mol^{-1}$ and $114 \ g \ mol^{-1}$,respectively.)

Liquids $A$ and $B$ form an ideal solution in the entire composition range. At $350 \ K$,the vapour pressures of pure $A$ and pure $B$ are $7 \times 10^3 \ Pa$ and $12 \times 10^3 \ Pa$,respectively. The composition of the vapour in equilibrium with a solution containing $40 \ \text{mole percent}$ of $A$ at this temperature is

At $300 \ K$,the vapour pressure of a pure liquid $A$ is $70 \ mm \ Hg$. It forms an ideal solution with another liquid $B$. The mole fraction of $B$ in the solution is $0.2$ and the total vapour pressure of the solution is $84 \ mm \ Hg$ at the same temperature. What is the vapour pressure (in $mm \ Hg$) of pure liquid $B$ at $300 \ K$?

When ethanol is mixed with cyclohexane,cyclohexane reduces the intermolecular forces between ethanol molecules. In this case,the liquid pair shows:

$A$ mixture of phenol and aniline shows negative deviation from Raoult's law. This is due to the formation of