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(D) According to Einstein's photoelectric equation,the kinetic energy $(KE)$ of the ejected photoelectron is given by: $KE = h
u - \varphi$,where $h\

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$Cu$

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(D) According to Einstein's photoelectric equation,the kinetic energy $(KE)$ of the ejected photoelectron is given by: $KE = h
u - \varphi$,where $h
u$ is the energy of incident radiation and $\varphi$ is the work function of the metal.From this relation,it is clear that for a constant incident energy $(h
u)$,the kinetic energy $(KE)$ is inversely proportional to the work function $(\varphi)$ of the metal.Therefore,the metal with the highest work function will result in the lowest kinetic energy of the ejected photoelectrons.The order of work functions for the given metals is: $Cu (4.70 \ eV) > Ag (4.26 \ eV) > Li (2.90 \ eV) > Na (2.75 \ eV)$.Since $Cu$ has the highest work function,it will exhibit the lowest kinetic energy for the ejected photoelectrons.

Assuming that the incident radiation is capable of ejecting photoelectrons from all the given metals,the lowest kinetic energy of the ejected photoelectron is observed with which of the given metals?

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