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(D) Since the balls of the same colour are identical,the number of ways to select balls of a particular colour is equal to the number of balls of that

Vedclass · Accepted Answer

$879$

Vedclass · Answer

(D) Since the balls of the same colour are identical,the number of ways to select balls of a particular colour is equal to the number of balls of that colour plus one (for the case where no ball of that colour is selected).For $10$ white balls,the number of ways to select them is $(10 + 1) = 11$.For $9$ green balls,the number of ways to select them is $(9 + 1) = 10$.For $7$ black balls,the number of ways to select them is $(7 + 1) = 8$.The total number of ways to select any number of balls (including the case where no balls are selected) is $11 	imes 10 	imes 8 = 880$.Since we need to select one or more balls,we must exclude the case where no balls are selected at all.Therefore,the required number of ways is $880 - 1 = 879$.

Assuming the balls to be identical except for the difference in colours,the number of ways in which one or more balls can be selected from $10$ white,$9$ green,and $7$ black balls is:

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