At ...... ^circ C temperature,the mean kineti | vedclass

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Question

(C) The mean kinetic energy of an ideal gas molecule is given by the formula $E = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is

Vedclass · Accepted Answer

$-73$

Vedclass · Answer

(C) The mean kinetic energy of an ideal gas molecule is given by the formula $E = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature in Kelvin.Since the mean kinetic energy depends only on the absolute temperature $T$,for the mean kinetic energy of ${O_2}$ molecules to be equal to that of ${H_2}$ molecules,their absolute temperatures must be the same.Given that the temperature of ${H_2}$ is $-73^\circ C$,the temperature of ${O_2}$ must also be $-73^\circ C$ for their mean kinetic energies to be equal.Therefore,the correct option is $C$.

At $...... ^\circ C$ temperature,the mean kinetic energy of ${O_2}$ molecules will be the same as that of ${H_2}$ molecules at $-73^\circ C$.

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