At 0,^{circ}text{C},the value of the density | vedclass

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(C) The ideal gas equation is $PV = nRT$,where $n = \frac{m}{M_w}$ ($m$ is mass,$M_w$ is molar mass).Substituting $V = \frac{m}{\rho}$,we get $P \left

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$\frac{273}{373}x$

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(C) The ideal gas equation is $PV = nRT$,where $n = \frac{m}{M_w}$ ($m$ is mass,$M_w$ is molar mass).Substituting $V = \frac{m}{ho}$,we get $P \left( \frac{m}{ho} ight) = \frac{m}{M_w} RT$.Rearranging for the ratio of density to pressure,we get $\frac{ho}{P} = \frac{M_w}{RT}$.Let $y = \frac{ho}{P} = \frac{M_w}{RT}$.At $T_1 = 273\, 	ext{K}$ $(0\,^{\circ}	ext{C})$,$y_1 = x = \frac{M_w}{R(273)}$.At $T_2 = 373\, 	ext{K}$ $(100\,^{\circ}	ext{C})$,$y_2 = \frac{M_w}{R(373)}$.Taking the ratio: $\frac{y_2}{x} = \frac{273}{373}$.Therefore,$y_2 = \frac{273}{373}x$.

At $0\,^{\circ}\text{C}$,the value of the density of a fixed mass of an ideal gas divided by its pressure is $x$. At $100\,^{\circ}\text{C}$,this value will be

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