At 20 , ^circ C,the Ag^+ ion concentration in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The dissociation of silver chromate is given by: $Ag_2CrO_4(s) \rightleftharpoons 2Ag^+(aq) + CrO_4^{2-}(aq)$The solubility product expression is:

Vedclass · Accepted Answer

$1.6875 	imes 10^{-12}$

Vedclass · Answer

(C) The dissociation of silver chromate is given by: $Ag_2CrO_4(s) ightleftharpoons 2Ag^+(aq) + CrO_4^{2-}(aq)$The solubility product expression is: $K_{sp} = [Ag^+]^2 [CrO_4^{2-}]$Given that $[Ag^+] = 1.5 	imes 10^{-4} \, M$,the concentration of chromate ions is half the concentration of silver ions due to stoichiometry:$[CrO_4^{2-}] = \frac{[Ag^+]}{2} = \frac{1.5 	imes 10^{-4}}{2} = 0.75 	imes 10^{-4} \, M$Substituting these values into the $K_{sp}$ expression:$K_{sp} = (1.5 	imes 10^{-4})^2 	imes (0.75 	imes 10^{-4})$$K_{sp} = (2.25 	imes 10^{-8}) 	imes (0.75 	imes 10^{-4})$$K_{sp} = 1.6875 	imes 10^{-12}$

At $20 \, ^\circ C$,the $Ag^+$ ion concentration in a saturated solution of $Ag_2CrO_4$ is $1.5 \times 10^{-4} \, mol/L$. At $20 \, ^\circ C$,the solubility product of $Ag_2CrO_4$ would be:

Similar Questions

If $K_{sp}$ of $CaF_2$ at $25\,^{\circ}C$ is $1.7 \times 10^{-10}$,the combination amongst the following which gives a precipitate of $CaF_2$ is

For the precipitation reaction of $Ag^{+}$ ions with $NaCl$,which of the following statements is correct?

Which one of the following sulphides is only completely precipitated when the acidic solution is made dilute?

Two insoluble salts $MY$ and $NY_{3}$ have the same $K_{SP} = 6.2 \times 10^{-13}$ at room temperature. Which of the following statements is true regarding $MY$ and $NY_{3}$?

Which of the following sulphides has the lowest solubility product?

Vedclass Test Series

Exam Paper Generator

Online Exam Module