At $17\,^{\circ}C$ temperature,the volume of a gas is $400\, mL$. At what temperature will: $(i)$ the volume become double,and $(ii)$ the volume become half?

(N/A) According to Charles's Law,$V \propto T$ (at constant pressure),so $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.
Given: $V_1 = 400\, mL$,$T_1 = 17 + 273 = 290\, K$.
$(i)$ If $V_2 = 2 \times V_1 = 800\, mL$,then $T_2 = \frac{V_2 \times T_1}{V_1} = \frac{800 \times 290}{400} = 580\, K = 307\,^{\circ}C$.
$(ii)$ If $V_2 = \frac{V_1}{2} = 200\, mL$,then $T_2 = \frac{V_2 \times T_1}{V_1} = \frac{200 \times 290}{400} = 145\, K = -128\,^{\circ}C$.