At $T(K)$,the solubility product of $AgBr$ is $4 \times 10^{-13}$. What is its solubility in $0.1 \ M$ $KBr$ solution?

  • A
    $2 \times 10^{-6} \ M$
  • B
    $4 \times 10^{-10} \ M$
  • C
    $4 \times 10^{-12} \ M$
  • D
    $4 \times 10^{-14} \ M$

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