At $T \ K$,two liquids $A$ and $B$ form an ideal solution. The vapour pressures of pure liquids $A$ and $B$ at that temperature are $400 \ mm \ Hg$ and $600 \ mm \ Hg$ respectively. If the mole fraction of liquid $B$ is $0.3$ in the mixture,the mole fractions of $A$ and $B$ in the vapour phase respectively are

What is a non-ideal solution and what is meant by positive deviation from Raoult's law?

An example of a near-ideal solution is:

Which statement about the composition of vapour over an ideal $1:1$ molar mixture of benzene and toluene is correct? Assume the temperature is constant at $25\,^{\circ}C$. Vapour pressure data $(25\,^{\circ}C)$:
Benzene: $75\, mm\, Hg$
Toluene: $22\, mm\, Hg$

$A$ solution of two liquids boils at a temperature higher than the boiling point of either of them. Hence,the binary solution shows:

Liquid $M$ and liquid $N$ form an ideal solution. The vapour pressures of pure liquids $M$ and $N$ are $450 \ mmHg$ and $700 \ mmHg,$ respectively at the same temperature. Then the correct statement is: ( $x_M =$ mole fraction of $M$ in solution; $x_N =$ mole fraction of $N$ in solution; $y_M =$ mole fraction of $M$ in vapour phase; $y_N =$ mole fraction of $N$ in vapour phase)