At 25^{circ} C, the ionization constant for a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The hydrolysis constant $(K_h)$ for the salt of a weak base and a strong acid is given by the formula: $K_h = \frac{K_w}{K_b}$ Given that the ioni

Vedclass · Accepted Answer

$2.00 	imes 10^{-5}$

Vedclass · Answer

(A) The hydrolysis constant $(K_h)$ for the salt of a weak base and a strong acid is given by the formula: $K_h = \frac{K_w}{K_b}$ Given that the ionization constant of the weak base $(K_b)$ is $5.00 	imes 10^{-10}$ and the ionic product of water $(K_w)$ at $25^{\circ} C$ is $1.00 	imes 10^{-14}$. Substituting the values: $K_h = \frac{1.00 	imes 10^{-14}}{5.00 	imes 10^{-10}} = 0.20 	imes 10^{-4} = 2.00 	imes 10^{-5}$ Thus, the hydrolysis constant of anilinium chloride is $2.00 	imes 10^{-5}$.

At $25^{\circ} C$, the ionization constant for anilinium hydroxide is $5.00 \times 10^{-10}$. The hydrolysis constant of anilinium chloride is

Similar Questions

$pH$ of $NH_4Cl$ solution is $5.28$. Calculate the degree of hydrolysis $(h)$ of its $0.02 \ M$ solution.

What is hydrolysis? Give the difference between non-hydrolyzing and hydrolyzing ions.

An aqueous solution of aluminum chloride is acidic due to $........$.

Assertion $(A)$: The aqueous solution of $CH_3COONa$ is alkaline in nature.
Reason $(R)$: Acetate ion undergoes anionic hydrolysis.
The correct answer is

Which among the following salts turns blue litmus red in its aqueous solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module