At 300 K the average velocity of a gas is 3 | vedclass

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(A) The formula for average velocity is $\mu_{av} = \sqrt{\frac{8RT}{\pi M}}$.Since $\mu_{av} \propto \sqrt{T}$, we have the ratio $\frac{\mu_{av_1}}{

Vedclass · Accepted Answer

$6 	imes 10^2$

Vedclass · Answer

(A) The formula for average velocity is $\mu_{av} = \sqrt{\frac{8RT}{\pi M}}$.Since $\mu_{av} \propto \sqrt{T}$, we have the ratio $\frac{\mu_{av_1}}{\mu_{av_2}} = \sqrt{\frac{T_1}{T_2}}$.Given $T_1 = 300 \ K$, $T_2 = 1200 \ K$, and $\mu_{av_1} = 3 	imes 10^2 \ cm / s$.Substituting the values: $\frac{3 	imes 10^2}{\mu_{av_2}} = \sqrt{\frac{300}{1200}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Therefore, $\mu_{av_2} = 2 	imes 3 	imes 10^2 = 6 	imes 10^2 \ cm / s$.

At $300 \ K$ the average velocity of a gas is $3 \times 10^2 \ cm / s$. The average velocity (in $cm / s$) of it at $1200 \ K$ is

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