At $298 \text{ K}$, the specific conductance $(\kappa)$ of a $0.0020 \text{ M}$ $NaCl$ solution is $2.50 \times 10^{-4} \text{ S cm}^{-1}$. Calculate the molar conductivity $(\Lambda_m)$ of the solution in $\text{S cm}^2 \text{mol}^{-1}$.
- A$125$
- B$62.5$
- C$5$
- D$250$
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View SolutionWhat will be the concentration of $NaCl$ solution,if the molar conductivity and conductivity of $NaCl$ solution are $124.3 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ and $1.243 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$ respectively?
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DifficultMHT CET 2026
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