Easy
At a given temperature,the equilibrium constant for the reaction $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$ is $2.4 \times 10^{-3}$. At the same temperature,the equilibrium constant for the reaction $PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$ is:
- A$2.4 \times 10^{-3}$
- B$-2.4 \times 10^{-3}$
- C$4.17 \times 10^{2}$
- D$4.8 \times 10^{-2}$
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