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(B) Total number of toys in the box $= n = 10$.Number of defective toys $= 3$.Number of non-defective toys $= 10 - 3 = 7$.$A$ customer purchases only

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$0.7$

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(B) Total number of toys in the box $= n = 10$.Number of defective toys $= 3$.Number of non-defective toys $= 10 - 3 = 7$.$A$ customer purchases only a non-defective toy.Therefore,the number of favourable outcomes for the event that the toy is purchased $= m = 7$.The probability of an event is given by the ratio of the number of favourable outcomes to the total number of outcomes.$	ext{Probability} = \frac{m}{n} = \frac{7}{10} = 0.7$.

At a toy shop,there are $10$ toys in a box of which $3$ toys are defective. $A$ customer would purchase a non-defective toy only. The probability that a toy selected at random from the box is purchased by the customer is ..............

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