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(C) According to Boyle's Law, at constant temperature, $PV = 	ext{constant}$.Let the initial pressure be $P_1 = P$ and the initial volume be $V_1 = V

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increases by $25 \%$

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(C) According to Boyle's Law, at constant temperature, $PV = 	ext{constant}$.Let the initial pressure be $P_1 = P$ and the initial volume be $V_1 = V$.If the pressure is decreased by $20 \%$, the new pressure $P_2$ is $P - 0.20P = 0.8P$.Using the relation $P_1 V_1 = P_2 V_2$:$P \cdot V = (0.8P) \cdot V_2$$V_2 = \frac{PV}{0.8P} = \frac{V}{0.8} = 1.25V$.The change in volume is $\Delta V = V_2 - V_1 = 1.25V - V = 0.25V$.The percentage change in volume is $\frac{\Delta V}{V_1} 	imes 100 = \frac{0.25V}{V} 	imes 100 = 25 \%$.Since the value is positive, the volume increases by $25 \%$.

At constant temperature, the pressure of a gas is decreased by $20 \%$. What is the percentage change in volume?

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