How does the graph of the fraction of molecul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(N/A) The Maxwell-Boltzmann distribution curve shows how the fraction of molecules varies with kinetic energy at different temperatures. As the temper

Vedclass · Accepted Answer

Vedclass · Answer

(N/A) The Maxwell-Boltzmann distribution curve shows how the fraction of molecules varies with kinetic energy at different temperatures. As the temperature increases,the curve shifts and changes shape as follows:   Lower Temperature $(T)$ Higher Temperature $(T + 10)$   $(i)$ The curve is narrower. $(a)$ The curve is broader.   $(ii)$ The peak (maximum fraction of molecules) is higher. $(b)$ The peak (maximum fraction of molecules) is lower.   $(iii)$ The peak shifts towards the left (lower kinetic energy). $(c)$ The peak shifts towards the right (higher kinetic energy).   $(iv)$ $A$ smaller fraction of molecules possesses energy greater than the activation energy $(E_a)$. $(d)$ $A$ larger fraction of molecules possesses energy greater than the activation energy $(E_a)$.

How does the graph of the fraction of molecules versus kinetic energy change at different temperatures?

Similar Questions

Calculate the rate constant of a first-order reaction having a pre-exponential factor $A = 1.6 \times 10^{13} \ s^{-1}$ and $\frac{E_a}{2.303 RT} = 21$.

Which statement is true with respect to a catalyst?

For the reaction,following data is given,
$A \rightarrow B$; $K_1 = 10^{15} \exp \left( \frac{-2000}{T} \right)$
$C \rightarrow D$; $K_2 = 10^{14} \exp \left( \frac{-1000}{T} \right)$
The temperature at which $K_1 = K_2$ is ........... $K$ $(exp. = e)$

If the definition of the temperature coefficient of the reaction holds good for a reaction between $27^{\circ} C$ and $37^{\circ} C$,the activation energy for the reaction in $kJ \cdot mol^{-1}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Lower Temperature $(T)$	Higher Temperature $(T + 10)$
$(i)$ The curve is narrower.	$(a)$ The curve is broader.
$(ii)$ The peak (maximum fraction of molecules) is higher.	$(b)$ The peak (maximum fraction of molecules) is lower.
$(iii)$ The peak shifts towards the left (lower kinetic energy).	$(c)$ The peak shifts towards the right (higher kinetic energy).
$(iv)$ $A$ smaller fraction of molecules possesses energy greater than the activation energy $(E_a)$.	$(d)$ $A$ larger fraction of molecules possesses energy greater than the activation energy $(E_a)$.