At room temperature,disproportionation of an aqueous solution of in situ generated nitrous acid $(HNO_2)$ gives the species
- A$H_3O^{+}, NO_3^-$ and $NO$
- B$H_3O^{+}, NO_3^-$ and $NO_2$
- C$H_3O^{+}, NO^{-}$ and $NO_2$
- D$H_3O^{+}, NO_3^-$ and $N_2O$
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Similar Questions
The disproportionation products of $ortho-phosphorous$ acid are
$1 \text{ mole}$ of $MnO_4^{2-}$ disproportionates into $MnO_4^-$ and $MnO_2$ in an acidic medium. Calculate the percentage by mass of $Mn$ converted to $MnO_4^-$ (Molar mass of $Mn = 55 \ g/mol$).
Difficult
View Solution$PhCHO \xrightarrow{OH^{-}} PhCH_2OH + PhCOO^{-}$
This reaction is an example of -
This reaction is an example of -
Medium
View Solution$3 H_3PO_2 \xrightarrow{\Delta} (X) + PH_3;$ The reaction is:
Easy
View SolutionWhich one of the following does not undergo disproportionation reaction?
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