(A) The time period of a vibration magnetometer is given by the formula: $T = 2\pi \sqrt{\frac{I}{MH}}$.Here,$I$ is the moment of inertia and $M$ is t

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(A) The time period of a vibration magnetometer is given by the formula: $T = 2\pi \sqrt{\frac{I}{MH}}$.Here,$I$ is the moment of inertia and $M$ is the magnetic moment of the magnet,both of which remain constant.Thus,$T \propto \frac{1}{\sqrt{H}}$,which implies $H \propto \frac{1}{T^2}$.Given $T_A = 2 \ s$ and $T_B = 3 \ s$,we have the ratio:$\frac{H_A}{H_B} = \frac{T_B^2}{T_A^2} = \left(\frac{3}{2}\right)^2 = \frac{9}{4}$.Therefore,the ratio $H_A : H_B$ is $9:4$.

Class 12 Physics Magnetism and Matter Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

Medium

At two places $A$ and $B$,using a vibration magnetometer,a magnet vibrates in a horizontal plane. Its respective periodic times are $2 \ s$ and $3 \ s$. At these places,the Earth's horizontal components are $H_A$ and $H_B$ respectively. Then the ratio between $H_A$ and $H_B$ will be:

A
$9:4$
B
$3:2$
C
$4:9$
D
$2:3$

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Class 12

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Magnetism and Matter

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Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

Two magnets of same size and mass make respectively $10$ and $15$ oscillations per minute at a certain place. The ratio of their magnetic moments is

Medium

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To compare magnetic moments of two magnets by vibration magnetometer,the 'sum and difference method' is better because:

Easy

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The unit of the reduction factor of a tangent galvanometer is

Easy

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The time period of oscillation of a magnet in a vibration magnetometer is $1.5 \ s$. The time period of oscillation of another magnet similar in size,shape,and mass but having one-fourth magnetic moment than that of the first magnet,oscillating at the same place,will be.....$s$.

Medium

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Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is $T$. The time period of each magnet in the same field is

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At two places $A$ and $B$,using a vibration magnetometer,a magnet vibrates in a horizontal plane. Its respective periodic times are $2 \ s$ and $3 \ s$. At these places,the Earth's horizontal components are $H_A$ and $H_B$ respectively. Then the ratio between $H_A$ and $H_B$ will be:

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Two magnets of same size and mass make respectively $10$ and $15$ oscillations per minute at a certain place. The ratio of their magnetic moments is

To compare magnetic moments of two magnets by vibration magnetometer,the 'sum and difference method' is better because:

The unit of the reduction factor of a tangent galvanometer is

The time period of oscillation of a magnet in a vibration magnetometer is $1.5 \ s$. The time period of oscillation of another magnet similar in size,shape,and mass but having one-fourth magnetic moment than that of the first magnet,oscillating at the same place,will be.....$s$.

Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is $T$. The time period of each magnet in the same field is

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