An atomic bomb consists of two pieces of $_{92}U^{235}$ and a source of:

  • A
    Proton
  • B
    Neutron
  • C
    Meson
  • D
    Electron

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Similar Questions

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
${ }_{1}^{2} X +{ }_{1}^{2} X ={ }_{2}^{4} Y$
The binding energies per nucleon of ${ }_{1}^{2} X$ and ${ }_{2}^{4} Y$ are $1.1 \, MeV$ and $7.6 \, MeV$ respectively. The energy released in this process is in $MeV$.

In the nuclear fusion reaction ${ }_1 H^2+{ }_1 H^3 \rightarrow{ }_2 He^4+n$, if the repulsive potential energy between the two nuclei is $2.07 \times 10^{-14} \,J$, then the temperature at which the gases must be heated to initiate the reaction is (Boltzmann constant $k = 1.38 \times 10^{-23} \,JK^{-1}$).

The mass of a nucleus ${ }_Z^A X$ is less than the sum of the masses of $(A-Z)$ neutrons and $Z$ protons. The energy equivalent to this mass difference is the binding energy. $A$ heavy nucleus of mass $M$ can break into two light nuclei of masses $m_1$ and $m_2$ only if $M > (m_1+m_2)$. The masses of some neutral atoms are given in the table below:
${ }_1^1 H$: $1.007825 u$${ }_1^2 H$: $2.014102 u$${ }_1^3 H$: $3.016050 u$${ }_2^4 He$: $4.002603 u$
${ }_3^6 Li$: $6.015123 u$${ }_3^7 Li$: $7.016004 u$${ }_{30}^{70} Zn$: $69.925325 u$${ }_{34}^{82} Se$: $81.916709 u$
${ }_{64}^{152} Gd$: $151.919803 u$${ }_{82}^{206} Pb$: $205.974455 u$${ }_{83}^{209} Bi$: $208.980388 u$${ }_{84}^{210} Po$: $209.982876 u$

$1.$ The correct statement is:
$(A)$ The nucleus ${ }_3^6 Li$ can emit an alpha particle.
$(B)$ The nucleus ${ }_{84}^{210} Po$ can emit a proton.
$(C)$ Deuteron $({ }_1^2 H)$ and alpha particle $({ }_2^4 He)$ can undergo complete fusion.
$(D)$ The nuclei ${ }_{30}^{70} Zn$ and ${ }_{34}^{82} Se$ can undergo complete fusion.
$2.$ The kinetic energy (in $keV$) of the alpha particle, when the nucleus ${ }_{84}^{210} Po$ at rest undergoes alpha decay, is:
$(A)$ $5319$ $(B)$ $5422$ $(C)$ $5707$ $(D)$ $5818$

The Sun radiates energy continuously and maintains its brightness because:

The energy released by the fission of a single uranium nucleus is $200 \,MeV$. The number of fissions of uranium nucleus per second required to produce $16 \,MW$ of power is (Assume efficiency of the reactor is $50\%$).

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