The average weight of 3 men A, B, and C is 84 | vedclass

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(D) The sum of weights of $A, B,$ and $C$ is $3 	imes 84 = 252 \, kg$.When $D$ joins,the total weight of $A, B, C,$ and $D$ is $4 	imes 80 = 320 \,

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(D) The sum of weights of $A, B,$ and $C$ is $3 	imes 84 = 252 \, kg$.When $D$ joins,the total weight of $A, B, C,$ and $D$ is $4 	imes 80 = 320 \, kg$.Therefore,the weight of $D = 320 - 252 = 68 \, kg$.The weight of $E = D + 3 = 68 + 3 = 71 \, kg$.When $E$ replaces $A$,the new group is $B, C, D,$ and $E$. The sum of their weights is $4 	imes 79 = 316 \, kg$.So,$B + C + D + E = 316$.Substituting the values of $D$ and $E$: $B + C + 68 + 71 = 316$.$B + C + 139 = 316 \implies B + C = 316 - 139 = 177 \, kg$.Since $A + B + C = 252$,we have $A + 177 = 252$.Therefore,$A = 252 - 177 = 75 \, kg$.

Age (in years)	$8, 20, 26, 29$
Number of People	$3, 2, m, 1$

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