Balls are thrown vertically upward in such a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The maximum height $h$ reached by a ball thrown with initial velocity $u$ is given by $h = \frac{u^2}{2g}$.Given $h = 5 \ m$ and taking $g = 10 \

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(C) The maximum height $h$ reached by a ball thrown with initial velocity $u$ is given by $h = \frac{u^2}{2g}$.Given $h = 5 \ m$ and taking $g = 10 \ m/s^2$,we have $5 = \frac{u^2}{2 	imes 10}$,which gives $u^2 = 100$,so $u = 10 \ m/s$.The time taken to reach the maximum height (time of ascent) is $t = \frac{u}{g} = \frac{10}{10} = 1 \ s$.Since the next ball is thrown when the previous one is at its maximum height,the time interval between throwing two consecutive balls is $1 \ s$.Therefore,the number of balls thrown per minute is $\frac{60 \ s}{1 \ s/	ext{ball}} = 60 \ 	ext{balls/min}$.

Balls are thrown vertically upward in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is $5 \ m$,the number of balls thrown per minute will be

Similar Questions

Draw graphs $a \to t$,$v \to t$,and $x \to t$ for an object falling freely.

If a ball is thrown vertically upwards with speed $u$,the distance covered during the last $t$ seconds of its ascent is

Can a particle moving in a straight line have zero velocity and non-zero acceleration at any instant? Give an example.

From a balloon moving upwards with a velocity of $12\,ms^{-1}$,a packet is released when it is at a height of $65\,m$ from the ground. The time taken by it to reach the ground is...........$s$ $(g = 10\,ms^{-2})$.

$A$ balloon starts rising from the ground from rest with an upward acceleration of $2 \, m/s^2$. Just after $1 \, s$,a stone is dropped from it. The time taken by the stone to strike the ground is nearly ....... $s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module