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(D) Benzoic acid $(C_6H_5COOH)$ undergoes decarboxylation when heated with sodalime $(NaOH + CaO)$ to form benzene $(C_6H_6)$. Thus,$X$ is sodalime.Ph

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Sodalime and zinc dust

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(D) Benzoic acid $(C_6H_5COOH)$ undergoes decarboxylation when heated with sodalime $(NaOH + CaO)$ to form benzene $(C_6H_6)$. Thus,$X$ is sodalime.Phenol $(C_6H_5OH)$ undergoes reduction when heated with zinc dust $(Zn)$ to form benzene $(C_6H_6)$ and zinc oxide $(ZnO)$. Thus,$Y$ is zinc dust.Therefore,$X$ is sodalime and $Y$ is zinc dust. The correct option is $(D)$.

Benzoic acid gives benzene on being heated with $X$ and phenol gives benzene on being heated with $Y$. Therefore $X$ and $Y$ are respectively

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