Benzonitrile on reduction with stannous chlor | vedclass

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(D) The reaction described is the $Stephen$ reduction. $1$. Benzonitrile $(C_6H_5CN)$ reacts with stannous chloride $(SnCl_2)$ and hydrochloric acid $

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Benzaldehyde

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(D) The reaction described is the $Stephen$ reduction. $1$. Benzonitrile $(C_6H_5CN)$ reacts with stannous chloride $(SnCl_2)$ and hydrochloric acid $(HCl)$ to form an imine hydrochloride intermediate $(C_6H_5CH=NH \cdot HCl)$. $2$. Subsequent acid hydrolysis of this intermediate yields benzaldehyde $(C_6H_5CHO)$. $3$. The overall reaction is: $C_6H_5CN + 2[H]$ $\xrightarrow{SnCl_2/HCl} C_6H_5CH=NH$ $\xrightarrow{H_3O^+} C_6H_5CHO$.

Benzonitrile on reduction with stannous chloride $(SnCl_2)$ in the presence of hydrochloric acid $(HCl)$ followed by acid hydrolysis forms,

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