Benzyl isocyanide can be obtained from which | vedclass

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(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a cova

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$A$ and $B$ Only

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(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a covalent compound, and the nucleophilic attack occurs through the nitrogen atom of the ambident $CN^-$ ion.$2$. Reaction $B$: Benzylamine $(C_6H_5CH_2NH_2)$ undergoes the carbylamine reaction with $CHCl_3$ and $KOH$ (or $NaOH$) to form benzyl isocyanide $(C_6H_5CH_2NC)$.$3$. Reaction $C$: Bromobenzene does not undergo nucleophilic substitution with $AgCN$ under normal conditions due to the partial double bond character of the $C-Br$ bond.$4$. Reaction $D$: Aniline $(C_6H_5NH_2)$ undergoes the carbylamine reaction to form phenyl isocyanide $(C_6H_5NC)$, not benzyl isocyanide.$5$. Reaction $E$: $2-$Phenylethyl bromide reacts with $KCN$ to form $3-$phenylpropanenitrile $(C_6H_5CH_2CH_2CN)$.Therefore, benzyl isocyanide is obtained from reactions $A$ and $B$.

List-$I$ (Mixture of Compounds)	List-$II$ (Reagent used to distinguish)
$A$. Diethyl amine + Ethyl amine	$I$. Bromine water
$B$. Acetaldehyde + Acetone	$II$. $CHCl_3 + KOH, \Delta$
$C$. Ethanol + Phenol	$III$. Neutral $FeCl_3$
$D$. Benzoic acid + Cinnamic acid	$IV$. Ammonical silver nitrate

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$
$C$. Bromobenzene + $AgCN$
$D$. Aniline + $CHCl_3$ + $Aq. NaOH$
$E$. $2-$Phenylethyl bromide + $KCN$

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Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:$A$. Benzyl bromide + $AgCN$$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$$C$. Bromobenzene + $AgCN$$D$. Aniline + $CHCl_3$ + $Aq. NaOH$$E$. $2-$Phenylethyl bromide + $KCN$